Asked by Daisy
From a point 50 feet in front of a church, the angles of elevation to the base of the steeple and the top of the steeple are 35° and 47° 20', respectively. Find the height of the steeple.
I missed class this day and have no idea how to go about this problem. I'd really appreciate any help with this. Thanks in advance!
I missed class this day and have no idea how to go about this problem. I'd really appreciate any help with this. Thanks in advance!
Answers
Answered by
Reiny
Make a sketch showing the steeple on top of the church.
label the height of the church c and the height of the steeple as s
I see two right-angled triangles:
in the first:
tan 35° = c/50
c = 5tan35 = appr 35.01 m
in the second:
(c+s)/50 - tan 47.33333..
c+s= 54.248
so the church part is 35.01 m, and to the top of the steeple is 54.248
so the steeple is 54.248 - 35.01 = 19.24 m high
label the height of the church c and the height of the steeple as s
I see two right-angled triangles:
in the first:
tan 35° = c/50
c = 5tan35 = appr 35.01 m
in the second:
(c+s)/50 - tan 47.33333..
c+s= 54.248
so the church part is 35.01 m, and to the top of the steeple is 54.248
so the steeple is 54.248 - 35.01 = 19.24 m high
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