Asked by rory
A bullet of mass m= 0.0290 kg is fired along an incline and imbeds itself quickly into a block of wood of mass M= 1.55 kg. The block and bullet then slide up the incline, assumed frictionless, and rise a height H= 1.65 m before stopping. Calculate the speed of the bullet just before it hits the wood. Note. The block is kept from sliding down the incline initially by as small peg
Answers
Answered by
drwls
The distance H that is slides vertically up the incline can be used to determine the velocity V AFTER impact. Conservation of energy gives you
(1/2) V^2 = g H
Knowing V, you can then solve for v (the bullet velocity before impact). Get it from the conservation of momentum relation:
m v = (M+m) V
m = bullet mass
M = wood block mass
v = [(M+m)/m]*sqrt(2gH)
(1/2) V^2 = g H
Knowing V, you can then solve for v (the bullet velocity before impact). Get it from the conservation of momentum relation:
m v = (M+m) V
m = bullet mass
M = wood block mass
v = [(M+m)/m]*sqrt(2gH)