Asked by Anonymous

A cyclist is coasting at a steady speed of 17m/s but enters a muddy stretch where the effective coefficient of friction is 0.60.

What will be the speed upon emerging?

Answers

Answered by drwls
How long is the "muddy stretch"?

Are the bike tires rolling or skidding?

Whoever assigned this question apparently does not understand rolling motion.
Answered by Elena
You need the length of muddy stretch ‘s’
ma=F(fr) =μmg,
=> a= μg.
a=(v² -v₀²)/2s

μg=(v² -v₀²)/2s
v= sqrt(2sμg+ v₀²)
Answered by drwls
Elena apparently does not take into account that unless a tire is skidding, the friction at the point of contact does not slow the bike down. The point of contact is an instant center, kinematically speaking.
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