Question

Phthalates used as plasticizers in rubber and plastic products are believed to act as hormone mimics in human. The value of deltaHcombustion for dimethylphthalate (C10H10O4) is 4685 kJ/mol. Assume 1.035 g of dimethylphthalate is combusted in a calorimeter whose heat capacity (C calorimeter) is 7.293 kJ/Celsius at 20.142 Celsius. What is the final temperature of the calorimeter?

Answer 1

4685 kJ/mol x (1.035g/molar mass) = ? and convert to J.
q joules = Ccal x (Tfinal-Tinitial)
Solve for Tf. I would put Ccal in J.

Answer 2

How do you convert 4848.975 to J?

Answer 3

kJ x 1000 = J.
But where did you get 4868.97...?
4685 x (1.035/197...) isn't anywhere near that number. I think you did not divide by the molar mass of the phthalate.

Answer 4

Ok, yeah I somehow read that as a label not as part of the equation, so
4685*(1.035/194.21)= 24.97
24.97*1000=24967.69

So then would the final equation be:

24967.69=7.293(Tfinal-20.142)

Thank you by the way Im just really struggling with this.

Answer 5

Yes except you need to convert that 7.293 kJ to J.

Answer 6

Ok I got the answer!! Thank you!!