Asked by Hanu2012
An 18 m tall tree is broken during a severe storm. The distance from the base of the trunk to the point where the tip touches the ground is 12 m. At what height did the tree break?
Answers
Answered by
Steve
the standard 5-12-13 triangle fits the bill, but algebraically,
If the tree broke at height x,
12^2 + x^2 = (18-x)^2
x = 5
If the tree broke at height x,
12^2 + x^2 = (18-x)^2
x = 5
Answered by
Mehtab
x^2 + 12^2 = (18-x)^2
x^2 + 144 + x^2 - 36x + 324
144 = -36x + 324
-180 = -36x
-180/-36 = -36x/-36
5 = x
x^2 + 144 + x^2 - 36x + 324
144 = -36x + 324
-180 = -36x
-180/-36 = -36x/-36
5 = x
Answered by
Man
Mehtab made a slight error in his second step,it was suppose to be = instead or +
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