calculate the angles of an isosceles triangle in which each base angle in four times the vertical angle

Answer 1

Let vertical angle = A
Base angles = 4A (each)

Sum = 9A = 180
A = 20 degrees
Base angles = 80 degrees

Answer 2

let a vertical angle Be P
base angle =4P
sum =9A=20degree
80 degree of two sides and 20 degree of its base.

Answer 3

let the vertical angle be x

base=4x(each)
sum=9x=180¡ã
=4¡Á20=80¡ãof its vertical angle