Asked by umar
                calculate the angles of an isosceles triangle in which each base angle in four times the vertical angle
            
            
        Answers
                    Answered by
            drwls
            
    Let vertical angle = A
Base angles = 4A (each)
Sum = 9A = 180
A = 20 degrees
Base angles = 80 degrees
    
Base angles = 4A (each)
Sum = 9A = 180
A = 20 degrees
Base angles = 80 degrees
                    Answered by
            nashrah shareef
            
    let a vertical angle Be P
base angle =4P
sum =9A=20degree
80 degree of two sides and 20 degree of its base.
    
base angle =4P
sum =9A=20degree
80 degree of two sides and 20 degree of its base.
                    Answered by
            nashrah shareef
            
    let the vertical angle be x
base=4x(each)
sum=9x=180¡ã
=4¡Á20=80¡ãof its vertical angle
    
base=4x(each)
sum=9x=180¡ã
=4¡Á20=80¡ãof its vertical angle
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