Asked by sony
A circular plate of uniform thickness has a diameter of 56cm.A circular portion of diameter 42cm is removed from one edge of the plate .find the position of the center of mass of the remaining portion.
Answers
Answered by
drwls
The removed portion has 3/4 the diameter and 9/16 of the area and mass M of the full circular (56 cm dia) plate.
Measure CM location from the center of the larger full circle. The center of the cutout circular hole is 7 cm from the center of the large circle
[M - (9/16)M]*x = M*0 - (9/16)M*7
(7/16)x = -63/16
x = 63/7 = -9.0 cm
The CM is 9 cm from the center of the large circle, in the opposite direction from the center of the removed circle
Measure CM location from the center of the larger full circle. The center of the cutout circular hole is 7 cm from the center of the large circle
[M - (9/16)M]*x = M*0 - (9/16)M*7
(7/16)x = -63/16
x = 63/7 = -9.0 cm
The CM is 9 cm from the center of the large circle, in the opposite direction from the center of the removed circle
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