Asked by Rachel

This is the situation I have been given:

You are given three capacitors, one with a capacitance of 0.025 micro-farads, another with a capacitance of 0.05 micro farads, and the third with a capacitance of 0.015 micro-farads. Using only these capacitors, arranged in series, parallel, or any combination, create a capacitive circuit that achieves a target capacitance of 80 micro-farads.

...I can not find a way to arrange them that comes close to this goal. Can someone help me please?

Answers

Answered by drwls
I cannot find a way, either. The most capacitance you can achieve is by arranging all three capacitors in parallel, which results in only 0.09 uF capacitance.
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