Asked by mikey

verify the identity:

(cosx/1+sinx) + (1+sinx/cosx) = 2secx
Answered by mikey
sinxcosx/cos^2x-sin^2x=tanx/1-tan^2x
Answered by Steve
1st:
putting all over a common denominator,
= (cos^2 + (1+sin)^2)/(cos(1+sin))
= (cos^2 + 1 + 2sin + sin^2)/(cos(1+sin))
= (2 + 2sin)/(cos(1+sin))
= 2/cos
= 2sec
Answered by Steve
2nd:

sin2x/cos2x = tan2x
done
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