Asked by Mandy
Solution of middle terms expansion of (2x^2+1/x)^9
Answers
Answered by
Reiny
the middle term would be term(5)
term(5) = C(9,4) (2x^2)^5 (1/x)^4
= 126 (32x^10) (1/x^4)
= 4032 x^6
term(5) = C(9,4) (2x^2)^5 (1/x)^4
= 126 (32x^10) (1/x^4)
= 4032 x^6
Answered by
Steve
actually, since there are 10 terms, and the question asked for the middle term<b>s</b>, we have to include the next term:
C(9,5) (2x^2)^4 (1/x)^5
= 126 (16x^8) (1/x^5)
= 2016 x^3
C(9,5) (2x^2)^4 (1/x)^5
= 126 (16x^8) (1/x^5)
= 2016 x^3
Answered by
Reiny
yup, Steve is correct
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