Asked by Logan
Find the least common multiple of the monomials. 5a squared, and 16a cubed. Also 17b squared and 3b cubed. Could you show me how to do these.
Thank you,
Sandy
Thank you,
Sandy
Answers
Answered by
Steve
5a^2 = 5*a^2
16a^2 = 2^4 * a^2
take the highest power of each prime (assuming a is not divisible by 2 or 5)
LCM = 2^4*5*a^2 = 80a^2
17b^2 = 17*b^2
3b^3 = 3*b^3
LCM = 3*17*b^3 = 51b^3
The LCM is the smallest number that can be divided by each of the two given numbers.
another example: LCM(20,30,50,80):
20 = 2^2 * 5
30 = 2 * 3 * 5
50 = 2 * 5^2
80 = 2^4 * 5
LCM = 2^4 * 3 * 5^2 = 1200
16a^2 = 2^4 * a^2
take the highest power of each prime (assuming a is not divisible by 2 or 5)
LCM = 2^4*5*a^2 = 80a^2
17b^2 = 17*b^2
3b^3 = 3*b^3
LCM = 3*17*b^3 = 51b^3
The LCM is the smallest number that can be divided by each of the two given numbers.
another example: LCM(20,30,50,80):
20 = 2^2 * 5
30 = 2 * 3 * 5
50 = 2 * 5^2
80 = 2^4 * 5
LCM = 2^4 * 3 * 5^2 = 1200
Answered by
Stack
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