Asked by Anonymous

A survey team is trying to estimate the height of a mountain above a level plain. From one point on the plain, they observe that the angle of elevation to the top of the mountain is 24. From a point 1000 feet closer to the mountain along the plain, they find that the angle of elevation is 27.
How high (in feet) is the mountain?

Answers

Answered by Reiny
Make a sideview sketch
you should have 2 triangles, one right-angled containing the height and a scalene triangle with angles 24° , 153° (the supplement of 27°) and 3°
the side opposite the 3° angle is 1000
by let the side opposite the 24° be x, (also the hypotenuse of the right-angled triangle)

x/sin24 = 1000/sin3
x = 1000sin24/sin3

let the height of the mountain be h
sin 27 = h/x
h = x sin27 = (1000sin24/sin3)(sin27)
= 3528.25
Answered by Hello
what....the......heck...is....trig..........
Answered by henry2,
d = hor. distance from foot of mountain to point where 24 deg. is measured.
Tan24 = h/d, h = d*Tan24.
Tan27 = h/(d-1000), h = (d-1000)Tan27.

d*Tan24 = (d-1000)*Tan27,
d = (d-1000)*1.11,
0.9d = d-1000,
d = 10,000 Ft.
h = d*Tan24 = 4,450 Ft.
Answered by Cole
Howdy everyone, here's the equation you need for this:
tan 24 = h/((h/(tan 27)) + 1000)

Just plug your numbers into that equation and you'll have the right answer.
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