Asked by Alex
The following equations are intepretations of the evidence from the reactions of four metals with various cation solutions. Make a table of half-reactions and arrange the four metallic ions and the hydrogen ions in order of their decreasing tendency to react. Label the strongest oxidizing agent and reducing agent.
Cd + 2H+ --> Cd2+ + H2
Hg + 2H+ --> Hg2+ + H2
Be + Cd2+ --> Be2+ + Cd
Ca2+ + Be --> Ca + Be
So I identified Cd, Hg, Be as the reducing agents and 2H+, Cd2+, Ca2+ as the oxidizing agents.
Now when making the table I can't identify which ones are the strongest and weakest. I know the method to do it. But for this question I don't know in what order they go. Can anyone help me?
Cd + 2H+ --> Cd2+ + H2
Hg + 2H+ --> Hg2+ + H2
Be + Cd2+ --> Be2+ + Cd
Ca2+ + Be --> Ca + Be
So I identified Cd, Hg, Be as the reducing agents and 2H+, Cd2+, Ca2+ as the oxidizing agents.
Now when making the table I can't identify which ones are the strongest and weakest. I know the method to do it. But for this question I don't know in what order they go. Can anyone help me?
Answers
Answered by
DrBob222
Alex, I'm sorry but I can't help you with this. First, I don't think Hg will displace H ion to produce H2. Second, I don't see anyway of resolving if Cd is above or below Hg even if I believed that Hg would displace H. I don't believe in making up problems in which the data is not true. Are you allowed to use any other information, such as that which you posted last night (similar problem)? That might help, I don't know. From these data, you CAN say that Be is above Ca and that Be is above Cd ; also that Cd and Hg are above H, but there is no way I can see to place these two groups together.
Answered by
Alex
OH! I just realized that Ca2+ + Be and Hg + 2H+ are actually nonspontaneous reactions.
Answered by
DrBob222
Thanks for letting me know. That sure makes the problem go from impossible to a two second problem.
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