Asked by joe
the half-life of cobalt-60 is 5.20 years.. how many milligrams of a 2.000-mg sample remains after 6.55 years
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
ln(No/N) = kt
No = 2.000 mg
N calculate
k from above
t 6.55 years.
ln(No/N) = kt
No = 2.000 mg
N calculate
k from above
t 6.55 years.
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