Asked by Anonymous
What is the derivative of (x^2+4x+5)/(x^3-2x)?
Answers
Answered by
Reiny
quotient rule !
dy/dx = ( (x^3 - 2x)(2x + 4) - (x^2 + 4x + 5)(3x^2 - 2) )/(x^3 - 2x)^2
= etc
dy/dx = ( (x^3 - 2x)(2x + 4) - (x^2 + 4x + 5)(3x^2 - 2) )/(x^3 - 2x)^2
= etc
Answered by
Anonymous
I know you use quotient rule. Is the answer (-x^4-8x^3-17x^2+8x+10)/(x^3-2x)^2
Thanks Reiny!
Thanks Reiny!
Answered by
Reiny
If you are taking Calculus, surely you should have no difficulty expanding and simplifying
(x^3 - 2x)(2x + 4) - (x^2 + 4x + 5)(3x^2 - 2)
I will leave that up to you to check if your answer is correct.
(hint: the answer is yes)
(x^3 - 2x)(2x + 4) - (x^2 + 4x + 5)(3x^2 - 2)
I will leave that up to you to check if your answer is correct.
(hint: the answer is yes)
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