Asked by Allyx32
From previous experiments, you have the following information.
N2(g)+O2(g)<--->2NO(g) Kc=2.3*10^-19
2NO(g)+O2(g)<--->2NO2(g) Kc=3*10^6
using that information, how many moles of NO2(g) will be made if you started with 1 moles of N2(g) and 2 moles of O2 (g)?
N2(g)+2O2(g)<--->2NO2(g)
N2(g)+O2(g)<--->2NO(g) Kc=2.3*10^-19
2NO(g)+O2(g)<--->2NO2(g) Kc=3*10^6
using that information, how many moles of NO2(g) will be made if you started with 1 moles of N2(g) and 2 moles of O2 (g)?
N2(g)+2O2(g)<--->2NO2(g)
Answers
Answered by
DrBob222
The reaction equation is just the sum of equation 1 and equation 2. Therefore, Kc for the reaction equation is k1*k2 = 6.9E-13
............N2 + 2O2 ==> 2NO2
I...........1.....2.......0
C..........-x....-2x......+2x
E..........1-x..2-2x.......2x
Substitute into Kc expression for the new reaction and solve. You want to find 2x = mols NO2
............N2 + 2O2 ==> 2NO2
I...........1.....2.......0
C..........-x....-2x......+2x
E..........1-x..2-2x.......2x
Substitute into Kc expression for the new reaction and solve. You want to find 2x = mols NO2
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