Asked by Lydia
How do I balance the following equation by the half-reaction method (it takes place in basic solution)?
Fe(OH)2(s) + O2(g) = Fe(OH)3(s)
the answer is 4Fe(OH)2(s) + 2H20(l) + O2(g) = 4Fe(OH)3(s) but how do I work it out?
Fe(OH)2(s) + O2(g) = Fe(OH)3(s)
the answer is 4Fe(OH)2(s) + 2H20(l) + O2(g) = 4Fe(OH)3(s) but how do I work it out?
Answers
Answered by
DrBob222
Here is a set of rules for balancing half reactions in both acid and basic solutions.
http://www.chemteam.info/Redox/Redox.html
http://www.chemteam.info/Redox/Redox.html
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