Asked by rebekah

The complete combustion of octane, C8H18, the main component of gasoline, proceeds as follows.
2 C8H18(l) + 25 O2(g) ¨ 16 CO2(g) + 18 H2O(g)

Octane has a density of 0.692 g/mL at 20‹C. How many grams of O2 are required to burn 26.5 gal of C8H18?

i got 1.22e5 but it is wrong
Answered by DrBob222
If you will post your work I will find the error.
Answered by rebekah
i cannot find my exact work but i converted 26.5 gal C8H18 to ml then used the density to get grams then converted grams to moles of C8H18 then to moles of )2 then grams of O2
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