Asked by Vicky
Calculate the amount (volume) of 0.135 M HClO4 solution required to neutralize 57.00 mL of .089 M NaOH
Answers
Answered by
DrBob222
This is a 1:1 acid/base reaction.
HClO4 + NaOH ==> NaClO4 + H2O
mL1 x M1 = mL2 x M2
Substitute and solve for the unknown.
HClO4 + NaOH ==> NaClO4 + H2O
mL1 x M1 = mL2 x M2
Substitute and solve for the unknown.
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