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The following reation has the following standard thermodynamic parameters: delta H= -33.6 kJ/mol delta S= -59.8 J/(mol*K). C(g) + D(g) --> E(g)

Calculate the temperature at which the reaction becomes nonspontaneous.
13 years ago

Answers

DrBob222
dG = dH - TdS
Set dG = 0 and solve for T
T = dH/dS = -33.6/-0.0598 = ?
13 years ago

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