Asked by an

If motion of a particle of mass (m) is given by y=ut+1/2gt^2 (square).find force acting on it
Answered by Damon
I assume that u and g are constants (in fact initial velocity and gravity)

dy/dt = speed = u + g t

d^2y/dt^2 = acceleration = g

F = m a
so
F = m g
Answered by ruchika
Not too bad
Answered by Mokibul
Wrote
Answered by Anonymous
dy/dt = speed = u + g t

d^2y/dt^2 = acceleration = g

F = m a
so
F = m g
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