Question
If motion of a particle of mass (m) is given by y=ut+1/2gt^2 (square).find force acting on it
Answers
Damon
I assume that u and g are constants (in fact initial velocity and gravity)
dy/dt = speed = u + g t
d^2y/dt^2 = acceleration = g
F = m a
so
F = m g
dy/dt = speed = u + g t
d^2y/dt^2 = acceleration = g
F = m a
so
F = m g
ruchika
Not too bad
Mokibul
Wrote
Anonymous
dy/dt = speed = u + g t
d^2y/dt^2 = acceleration = g
F = m a
so
F = m g
d^2y/dt^2 = acceleration = g
F = m a
so
F = m g