Question

if 27 grams of ice at 0 degrees celsius is added to 123 grams of water at 100 degrees celsius in an insulated container, calculate the final temperature. assume specific heat of water is 4.184 J/K g

Answer 1

1. ice melts at zero C. q = <b>mass ice x heat fusion</b>

2. melted water at zero changes temperature to Tfinal.
q = <b>[mass melted ice x specific heat H2O x (Tfinal-Tinitial)]</b>

3. Warm water at 100 C cools to Tfinal
q = <b>[mass warm water x specific heat H2O x (Tfinal-Tinitial)]</b>

Add 1 + 2 + 3 together (I have put them in boldface type) and they equal = 0. Solve for Tfinal