Asked by alexus
Jackie exerts a 43 N horizontal force as she pulls a sled that weighs 140 N across a cement sidewalk at a constant speed. What is the coefficient of kinetic friction between the sidewalk and the sled?
Answers
Answered by
Jennifer
43 - ckf * 140 = m*a
where ckf is coefficient of kinetic friction. In your textbook ckf is probably represented as the greek letter mu, but it's really hard to write greek letters here. . .
m is the mass of the sled, and a is its acceleration. Since the sled is moving at a constant speed, the acceleration is 0, or
43 - ckf * 140 = 0
Solve for ckf
where ckf is coefficient of kinetic friction. In your textbook ckf is probably represented as the greek letter mu, but it's really hard to write greek letters here. . .
m is the mass of the sled, and a is its acceleration. Since the sled is moving at a constant speed, the acceleration is 0, or
43 - ckf * 140 = 0
Solve for ckf
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