Asked by Avery

Two cars, 127 miles apart, start moving towards each other at the same time. One is moving 3 times as fast as the other. If they meet 1.5 hrs later, find the average speed of the slower car in miles per hour?

Answers

Answered by Steve
slower car moves 127/4 miles in 1.5 hrs

(127/4 mi) / 1.5hr = 21.17 mi/hr
Answered by Avery
Sorry, how did you get that? :(
Answered by Elena
v1•t+v2•t=s
v1=v, v2=3v,
v•t+3v•t=4•v•t=s
v=s/4•t =127/4•1.5 =21.17 mph
Answered by Avery
Oh! I understand now, thanks so much to both :)
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