Asked by John
The hard disk in a laptop computer contains a small disk that rotates at a rate of 5000 rpm. If this disk has a radius of 2.3 cm, what is the centripetal acceleration of a point at the edge of the disk?_____m/s^2
Answers
Answered by
Elena
n= 5000 rpm =83.33 rev/s
ω=2πn=2•π•83.33=523.6 rad/s.
a(centr) = ω²R=523.6²•0.023=6305.6 m/s²
ω=2πn=2•π•83.33=523.6 rad/s.
a(centr) = ω²R=523.6²•0.023=6305.6 m/s²
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.