m2•a=T - m2•g•sinα => T= m2•a + m2•g•sinα
m1•a=m1•g – T= m1•g - m2•a - m2•g•sinα.
a=g•(m1-m2•sinα)/(m1+m2) = 9.8•(7.93-5.13• sin40°)/(7.93+5.13) =
=3.48 m/s²,
T= m1(g-a)= 7.93•(9.8-3.48) = 50.15 N.
Two packing crates of masses 7.93 kg and 5.13 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 5.13 kg crate lies on a smooth incline of angle 40.0°.
a) Find the acceleration of the 5.13 kg crate
B)Find the tension in the string
1 answer