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A student is skateboarding down a ramp that is 5.5 m long and inclined at 19° with respect to the horizontal. The initial speed...Asked by Sally
A student is skateboarding down a ramp that is 8.48 m long and inclined at 16.4° with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp is 3.94 m/s. Neglect friction and find the speed at the bottom of the ramp.
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Answered by
Elena
KE1 +PE = KE2
m•v₀²/2 + m•g•h = m•v²/2
v=sqrt(v₀² + 2•g•h) =
= sqrt(v₀² + 2•g•s•sinα)
m•v₀²/2 + m•g•h = m•v²/2
v=sqrt(v₀² + 2•g•h) =
= sqrt(v₀² + 2•g•s•sinα)
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