Yoga fun: 63 + 12n
Yoga: 15n
when is 15n = 63 + 12n
15n - 12n = 63
3n=63
n = 21
21 classes would cost the same for either club
Yoga: 15n
when is 15n = 63 + 12n
15n - 12n = 63
3n=63
n = 21
21 classes would cost the same for either club
Let's assume the number of classes is represented by "x."
For Yoga Fun, the cost equation is: Cost at Yoga Fun = $63 + ($12 * x)
For Yoga for All, the cost equation is: Cost at Yoga for All = $15 * x
To find the number of classes that will result in the same cost at both places, we'll set the two cost equations equal to each other:
$63 + ($12 * x) = $15 * x
Now, we can solve the equation:
$63 + $12x = $15x
To eliminate the variable "x" from one side of the equation, we'll subtract $12x from both sides:
$63 = $15x - $12x
$63 = $3x
Divide both sides by $3:
$63 / $3 = $3x / $3
21 = x
So, the cost will be the same at both places after 21 classes.
Therefore, if you attend 21 classes, the total cost at Yoga Fun and Yoga for All will be equal.
Let's assume the number of classes is represented by "x."
For Yoga Fun, the cost is given as $63 as a starting fee plus $12 per class:
Cost at Yoga Fun = $63 + ($12 * x)
For Yoga for All, there is no starting fee, so the cost is simply $15 per class:
Cost at Yoga for All = $15 * x
We want to find the number of classes where the costs are equal, so we can set up the equation:
$63 + ($12 * x) = $15 * x
Now, we can solve for "x" by using algebraic techniques.
First, let's move all the terms with "x" to one side:
$12 * x - $15 * x = $63
Next, let's combine like terms:
$3 * x = $63
Finally, divide both sides of the equation by $3 to solve for "x":
x = $63 / $3
x = 21
Therefore, the cost will be the same at both Yoga Fun and Yoga for All after 21 classes.