Asked by Henry
If the quadratic equation x^2 + bx +c=0 has exactly one solution r, then find b/c.
Answers
Answered by
Steve
x^2 + bx + c = (x-r)^2
2r = -b
r^2 = c
b/c = r^2/(-r/2) = -2r
2r = -b
r^2 = c
b/c = r^2/(-r/2) = -2r
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