Question

A 0.1kg ball dropped on the floor hits with a speed of 4.0m/s and rebounds at a speed of 3.8m/s. Calculate the impulse delivered to the ball by the floor.

Answer 1

The impulse delivered to the ball is the change in momentum

The beginning momentum is the mass of the object multiplied by its initial speed (0.1 kg * 4.0 m/s) = .4 kg m/s

The final momentum is the mass of the object multiplied by its final speed (0.1 kg * 3.8 m/s) = 0.38 kg m/s

Impulse = .4N - .38 N = 0.02 kg m/s

Answer 2

a ball of mass 200g moving with velocity of 15m/s rebounce with 6m/s find the impulse if the duration of the impulse is 0.01s