Asked by Carolina
4 ^ (3x–1) = 1.5625 × 10 ^(–2)
Answers
Answered by
Steve
(3x-1) log4 = log .015625
3x-1 = log.015625/log4
x = (1 + log.015625/log4)/3 = -2/3
3x-1 = log.015625/log4
x = (1 + log.015625/log4)/3 = -2/3
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