78 g of potassium (K) react with 71 g of chlorine (Cl) to produce potassium chloride. According to the Law of Conservation of Mass, what is the mass of the product (2KCl)? (1 point)

Question

Responses

4 g
4 g

149 g
149 g

156 g
156 g

2 g

Answer 1

According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products.

In this reaction, we have:

• Mass of potassium (K) = 78 g
• Mass of chlorine (Cl) = 71 g

To find the mass of the products (potassium chloride, KCl), we can add the masses of the reactants:

\[ \text{Mass of products} = \text{Mass of K} + \text{Mass of Cl} = 78 , \text{g} + 71 , \text{g} = 149 , \text{g} \]

Thus, the mass of the product \(2KCl\) is 149 g.

So the correct response is 149 g.