Given triangle ABC, AD bisects angle BAC,and AE=ED

Prove AE/AC=BD/BC

Because I cant draw it I will explain. Its a triangle, A is the point at the top, B is the point at the bottom left and C is the point at the bottom right.There is a line going right down the middle, which is point D. So point D is between point B and C. From point D there is a short line which goes to the middle of points A and C, this point is E.

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