Question
How high will a 1.85 kg rock go if thrown straight up by someone who expends 80.0 J of energy on it?
Answers
Damon
Kinetic energy at ground = 80
Kinetic energy at max height = 0
so
Potential energy at max height = 80
so
m g h = 80
h = 80/(1.85*9.81)
Kinetic energy at max height = 0
so
Potential energy at max height = 80
so
m g h = 80
h = 80/(1.85*9.81)
Anonymous
Kinetic energy at ground = 80
Kinetic energy at max height = 0
so
Potential energy at max height = 80
so
m g h = 80
h = 80/(1.85*9.81)
Kinetic energy at max height = 0
so
Potential energy at max height = 80
so
m g h = 80
h = 80/(1.85*9.81)