Asked by Tyson
                Two sides of a triangle are x units and y units in length. The angle between them is theta. Prove that the area of the triangle is 1/2xysin(theta). 
I'm not sure how to do this question, I tried drawing a picture but I'm still not understanding it.
            
        I'm not sure how to do this question, I tried drawing a picture but I'm still not understanding it.
Answers
                    Answered by
            Reiny
            
    draw a perpendicular from side x to side y, let it be h
Area of triangle
= (1/2)base x height
= (1/2) y h
but sinØ = h/x
h = xsinØ
so area =(1/2) y xsinØ
= (1/2)xy sinØ
    
Area of triangle
= (1/2)base x height
= (1/2) y h
but sinØ = h/x
h = xsinØ
so area =(1/2) y xsinØ
= (1/2)xy sinØ
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