Asked by Dani
A car of mass m = 1635 kg is pushed off a cliff of height h = 23 m. If the car lands a distance of 9 m from the base of the cliff, what was the kinetic energy of the car the instant after it left the cliff?
Answers
Answered by
bobpursley
how long is it in the air?
h= 1/2 g t^2
time in air=sqrt(2h/g)=sqrt(46/9.8) you figure that.
now 9m=vhoriz*time in air. Figure Velocity horizontal v
then KE=1/2 m v^2
h= 1/2 g t^2
time in air=sqrt(2h/g)=sqrt(46/9.8) you figure that.
now 9m=vhoriz*time in air. Figure Velocity horizontal v
then KE=1/2 m v^2
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