A bicycle wheel of radius 0.4 m is spinning at a rate of 40 revolutions per minute.

What is the centripetal acceleration of a point on the edge of the wheel?

What is the period of the wheel's motion?

1 answer

40rpm=80PI/60 radians/s =1 1/3 PI rad/s=w

centripetal acceleartion=w^2 r

Period=1/freq=2PI/w