Question

What mass of solid aluminum hydroxide can be produced when 50.0 mL of 0.200 M aluminum nitrate is added to 200.0 mL of 0.100M potassium hydroxide?
Step 1. Write the equation and balance it.
Al(NO3)3 + 3KOH --> Al(OH)3 + 3KNO3

Step 2. Convert what you have to mols.
mols = M x L
mols Al(NO3)3 = 0.2 x 0.05 = ??
mols KOH = 0.1 x 0.200 = ??

Step 3. Determine the limiting reagent (that looks like it is KOH but check me out on that).

Step 4. Determine mols Al(OH)3.
Step 5. Convert mols to grams.
grams = mols x molar mass.

Post your work if you get stuck AND explain in detail what you don't understand.
.520g of Al(OH)3
git griefed
Sorry, I think it is 5.20g.

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