Asked by omar

What mass of solid aluminum hydroxide can be produced when 50.0 mL of 0.200 M aluminum nitrate is added to 200.0 mL of 0.100M potassium hydroxide?

Answers

Answered by DrBob222
Step 1. Write the equation and balance it.
Al(NO3)3 + 3KOH --> Al(OH)3 + 3KNO3

Step 2. Convert what you have to mols.
mols = M x L
mols Al(NO3)3 = 0.2 x 0.05 = ??
mols KOH = 0.1 x 0.200 = ??

Step 3. Determine the limiting reagent (that looks like it is KOH but check me out on that).

Step 4. Determine mols Al(OH)3.
Step 5. Convert mols to grams.
grams = mols x molar mass.

Post your work if you get stuck AND explain in detail what you don't understand.
Answered by ngan
.520g of Al(OH)3
Answered by popbob
git griefed
Answered by bobpop
Sorry, I think it is 5.20g.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions