throwing 2 dice and flipping a coin.
suppose you want the prob(heads and a sum of 7)
the process of flipping the coin has no effect on the act of throwing the dice.
Thus the events are "independent"
What is an example of two events that are neither disjoint nor independent?
(I have no idea how that would even work)
3 answers
sorry I misread your question
If the sets are not disjoint then they have elements in common.
for example
the set A containing numbers 1 through 7. There is only one of each number in the set.I can only pick from set A
and
the set B containing numbers 6 through 9. There is only one of each number in the set. You can only pick from set B
Is the probability of picking a number from set B changed by the previous random selection of a number from box A?
Sure it is. If I took the six or the seven from set A, I took it from the intersection, and you can not pick it. Therefore the events are not independent.
for example
the set A containing numbers 1 through 7. There is only one of each number in the set.I can only pick from set A
and
the set B containing numbers 6 through 9. There is only one of each number in the set. You can only pick from set B
Is the probability of picking a number from set B changed by the previous random selection of a number from box A?
Sure it is. If I took the six or the seven from set A, I took it from the intersection, and you can not pick it. Therefore the events are not independent.
2 answers