Asked by John
How to solve titration problem for HC2H3O2 + NaOH= NaC2H3O2 + H2O
The M of NaOH= 0.427
The volume of NaOH= 17.30mL
10.00mL of acid
The second titration calculation is:
The M of NaOH= 0.427
The volume of NaOH=34.60mL
20.00mL of acid
The M of NaOH= 0.427
The volume of NaOH= 17.30mL
10.00mL of acid
The second titration calculation is:
The M of NaOH= 0.427
The volume of NaOH=34.60mL
20.00mL of acid
Answers
Answered by
DrBob222
mols NaOH = M x L = ?
mols HAc = mols NaOH (look at the coefficients in the balanced equation).
M acid = mols acid/L acid.
mols HAc = mols NaOH (look at the coefficients in the balanced equation).
M acid = mols acid/L acid.
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