Asked by Amber
find a polynomial of least degree(having real coefficients) with zeros: 5, -2, 2i
Answers
Answered by
bobpursley
multiply this out:
(x-5) (x^2+4)
I suspect you copied the problem wrong, it should be zeroes at 5, -2i, 2i
(x-5) (x^2+4)
I suspect you copied the problem wrong, it should be zeroes at 5, -2i, 2i
Answered by
Steve
Unless there is the implicit assumption that if 2i is a root, so is -2i, so the polynomial would be
(x-5)(x+2)(x^2+4) = x^4 - 3x^3 - 6x^2 - 12x - 40
(x-5)(x+2)(x^2+4) = x^4 - 3x^3 - 6x^2 - 12x - 40
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.