it takes 5 s to stop the car __ 55 / 11
the average speed (Va) is __ (55 + 0) / 2
the stopping distance is __ Va * 5
twice as fast means that the stopping time is doubled, along with the average speed
__ this means that the car travels 4 times as far
a race car can be slowed with a constant acceleration of -11m/s2.
a.if the car is going 55m/s,how many meters will it travel beofre it stops?
b.how many metes will it take to stop a car going twice as fast?
1 answer