Asked by Mackenzie
                your social security number is a 9 digit number.  suppose that the last 4 digits are chosen randomly from the number 0-9.  
a. how many sequences are possible for the last 4 digits?
b. what is the probability of getting 5 or 0 in the last digit.
c. what is the probability of getting two 5's in the last two digits?
            
        a. how many sequences are possible for the last 4 digits?
b. what is the probability of getting 5 or 0 in the last digit.
c. what is the probability of getting two 5's in the last two digits?
Answers
                    Answered by
            drwls
            
    a.) 0000 through 9999 = 10,000 possibilities
b.) 1/10 + 1/10 = 1/5
c.) 1 (55) out of 100 (00 through 99)
    
b.) 1/10 + 1/10 = 1/5
c.) 1 (55) out of 100 (00 through 99)
                    Answered by
            Mackenzie
            
    for a i thought you were supposed to do 9*8*7*6 and the answer that i got was  3,024.  
for b i got 9*8=72
for c i got 9*9=81
does that make sense
    
for b i got 9*8=72
for c i got 9*9=81
does that make sense
                    Answered by
            PsyDAG
            
    The numerals get smaller if you are considering probabilities <I>without replacement</I>. In other words, using a numeral in one position would prohibit its use in other positions. However, the use of any numeral does not effect the probabilities of the remaining numerals.
I hope this helps a little more. Thanks for asking.
    
I hope this helps a little more. Thanks for asking.
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