Asked by Anonymous
How many grams of urea [CO(NH2)2] would be required to prepare 200 mL of a 5.0 x 10-3 molar solution?
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Answered by
Steve
200mL of 5.0*10^-3M = 1.0*10^-3 moles of urea
so, figure mol wt and divide by 1000 to get grams needed
so, figure mol wt and divide by 1000 to get grams needed
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