Asked by Shay
The half-life for the radioactive decay of calcium-47 is 4.5 days.If a sample has an activity of 4.00uCi after 13.5 days, what was the initial activity of the sample?
Answers
Answered by
DrBob222
13.5days/4.5 days = 3 half lives.
(Activity/2<sup>3</sup>) = 4
Solve for activity.
(Activity/2<sup>3</sup>) = 4
Solve for activity.
Answered by
PIZZO
GGHHH
Answered by
Foster
Iron-59 has a half-life of 46 days. If the laboratory received a sample of 8.0 g of iron-59, the number of grams that are still active after 184 days is _