Asked by Shay

The half-life for the radioactive decay of calcium-47 is 4.5 days.If a sample has an activity of 4.00uCi after 13.5 days, what was the initial activity of the sample?
Answered by DrBob222
13.5days/4.5 days = 3 half lives.
(Activity/2<sup>3</sup>) = 4
Solve for activity.
Answered by PIZZO
GGHHH
Answered by Foster
Iron-59 has a half-life of 46 days. If the laboratory received a sample of 8.0 g of iron-59, the number of grams that are still active after 184 days is _
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