Asked by noorie

-What volume of .500 M Pb(NO3)2 is required to react completely with 18.25 L of .625 M Na2SO4?
Answered by DrBob222
Pb(NO3)2 + Na2SO4 ==> PbSO4 + 2NaNO3
mols Na2SO4 = M x L = ?
mols Pb(NO3)2 = 1/2 mol Na2SO4
M Pb(NO3)2 = mols Pb(NO3)2/L Pb(NO3)2. You have M and mols, solve for L.
Answered by noorie
thank you..
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