Asked by Lisa K.
In 1993, Javier Sotomayor set a world record of 2.43 m in the men's outdoor high jump. He is 193 cm(6ft 4in) tall. BY treating his body as a point located at half his height, given that he left the ground a horizontal distance from the bar 1.5 m at a takeoff angle of 65 degrees, determine Javier takeoff speed?
Answers
Answered by
Henry
Range = Vo^2*sin(2A)/g = 1.5 m.
Vo^2*sin(130)/9.8 = 1.5
0.078168Vo^2 = 1.5
Vo^2 = 19.19
Vo = 4.38 m/s.
Vo^2*sin(130)/9.8 = 1.5
0.078168Vo^2 = 1.5
Vo^2 = 19.19
Vo = 4.38 m/s.
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