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A function is given below. Determine the average rate of change of the function between

t = 9
and
t = 9 + h.
f(t) =

Square root of 4t

1 answer

f(t) = √4t
f(t+h) = √4(t+h)

f(9) = √36 = 6
√(9+h) = √(36t+4h)

avg rate of change is (√(36t+4h) - 6)/h
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