A boat has a mass of 6800 kg. Its engines generate a drive force of 4500 N, due west, while the wind exerts a force of 660 N, due east, and the water exerts a resistive force of 1200 N due east. What is the magnitude and direction of the boat's acceleration?

asked by Lacie

12 years ago

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1 answer

ma=ΣF= F(eng) –F(wind)-F9water) = >
a=(4500-660-1200)/6800 =0.388 m/s²

answered by Elena

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Question

A boat has a mass of 6800 kg. Its engines generate a drive force of 4500 N, due west, while the wind exerts a force of 660 N, due east, and the water exerts a resistive force of 1200 N due east. What is the magnitude and direction of the boat's acceleration?

1 answer

ma=ΣF= F(eng) –F(wind)-F9water) = >
a=(4500-660-1200)/6800 =0.388 m/s²

Elena · Answer

ma=ΣF= F(eng) –F(wind)-F9water) = > a=(4500-660-1200)/6800 =0.388 m/s²