Asked by Elliott

I've seen the posts on solving this particular equation, and I know the answer is right in front of me. I'm still having trouble understanding why...
a 42g piece of ice at 0.0 degrees C is added to a sample of water at 7.8 degrees C. All the ice melts and the temperature decreases to 0.0 degrees C. How many grams of water are in the sample?

I feel really dumb for asking such an obvious question, but I think I'm over-thinking it... Thanks!

Answers

Answered by DrBob222
(mass ice x heat fusion) + (mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0
Substitute and solve for mass H2O
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